JEE Main Result 2020 – National Testing Agency aka NTA will announce the result of JEE Main (Paper 1) on April 30 on official websites of JEE Main and NTA. Test-takers seeking admission in B.Arch or B.Planning will have to wait till May 15 to check the JEE Main 2020 result of Paper 2. However, due to COVID-19 pandemic, the exam dates have been postponed due to which the results may also get delayed. Candidates just need to enter their JEE Main application number and date of birth along with the security pin to check their JEE Main result. The JEE Main result for April session (Paper 1) will comprise of four NTA scores – one combined score, and separate scores of candidates in Physics, Chemistry, and Mathematics. This article will consist the vital information about JEE Main result 2020, such as important dates, how to download scorecard, past trends, and post result declaration events.
Latest Update: Due to the COVID-19 outbreak in the country, the JEE Main exam has been postponed and thus the result may also get delayed. According to latest announcement by a HRD Minister Ramesh Pokhriyal, the exam will now be conducted between 18th July 2020 and 23rd July 2020.
JEE Main Result – Important Dates
Below listed event calendar of JEE Main 2020 April session will help the aspirants keep abreast with the deadlines of the major events of JEE Main 2020.
Schedule of JEE Main Result 2020
| Event | Date |
| JEE Main application form 2020 | February 7 to March 12 |
| Admit card release date | March 16* |
| JEE Main exam 2020 | 18th July 2020 to 23rd July 2020 (latest update) |
| Result declaration | Paper 1 – April 30* Paper 2 – May 15* |
*Postponed/delayed due to COVID-19 outbreak. The fresh dates will be announced soon.
Click Here to start filling JEE Main Application Form 2020
JEE Main Result – Key Information
JEE Main aspirants need to know a few notable points about the result declaration:-
- Result of Paper 1 & 2 will be declared online on the official websites only.
- JEE Main scorecard 2020 will comprise NTA scores obtained by the candidate in first as well as in the second attempt along with the best of the two Total NTA scores.
- JEE (Main) authority will compile the overall merit list after merging the NTA scores of JEE Main January & April 2020.
- JEE Main result 2020 will also show the qualifying status of the candidates for JEE Advanced 2020.
- The best of two NTA scores will be considered for further admission process.
How to Download JEE Main Result 2020?
The steps discussed below will help candidates download their result of JEE Main 2020 seamlessly:-
- Visit the official website of NTA/ JEE Main 2020
- Click on the link for ‘JEE Main Result 2020’
- The login page for the result will open up as shown in the below screenshot
- Fill the boxes with needed information (application number, DOB, and security pin) and click submit
- JEE Main result 2020 (with sectional & overall NTA score) will display on the screen
- Download the result and take a printout for further reference
Click Here to check your JEE Main Result/ Scorecard 2020
Details mentioned on JEE Main Result 2020
- Name of the candidate
- Roll number
- Date of birth
- Name of the candidate’s parents
- State code of eligibility
- Category and Nationality
- Subject-wise NTA score
- Total NTA scores obtained (both attempts)
- Best of NTA scores (based on both attempts)
- AIR (All India Rank) of candidate
- Category-wise JEE Main cutoff 2020
JEE Main Result – Normalization Process
JEE Main score normalization process involves the following 3 steps:-
Step 1: Raw Score Calculation
The subject-wise and overall score of the candidates is calculated as per the below-mentioned marking scheme:
Overall Score of JEE Main = (Number of correct responses x 4) – (Number of wrong responses x 1)
Step 2: Percentile Score Calculation
Below, in this article, the percentile calculation process (subject-wise and overall) has been described. In order to avoid the probabilities of ties percentile scores with 7 decimal places are calculated.
Step 3: Factors determined for Tie-breaking
A tie between the JEE main scores of two or more candidates is a very rare situation. However, NTA has defined a few criteria to break the tie. These criteria are discussed below in this article.
JEE Main Result – Percentile Calculation
The result of JEE Main 2020 will be announced with the percentile-based NTA score of candidates in each subject (Physics, Chemistry, and Mathematics) and one overall (combined) score. Below formula will help test-takers understand the JEE Main result calculation better.
Formula to calculate NTA percentile
- Total Percentile (T1P) = 100 X Number of test-takers with a raw score equal to or less than T1 score/ Total number of candidates appeared in April session
- Physics Percentile (P1P) = 100 X Number of test-takers with a raw score equal to or less than P1 score/ Total number of candidates appeared in April session
- Chemistry Percentile (C1P) = 100 X Number of test-takers with a raw score equal to or less than C1 score/ Total number of candidates appeared in April session
- Mathematics Percentile (M1P) = 100 X Number of test-takers with a raw score equal to or less than M1 score/ Total number of candidates appeared in April session
JEE Main Result – Inter-Se Merit
In case of a tie between two or more candidates with same Total NTA score, inter-se merit shall be determined as per the below order:-
- NTA score in Mathematics, followed by
- NTA score in Physics, followed by
- NTA score in Chemistry, followed by
- Candidates with less negative responses, followed by
- Candidates older in age
Note- If the tie doesn’t break even after the above criteria, the same rank will be given to the candidates.
JEE Main Result – Proportion between Percentile and Marks
Candidates should know the proportion between marks and the percentile to understand their JEE Main score 2020 in a clearer manner.
Percentile V/S JEE Main Marks
| Percentile | JEE Main Marks |
| 100 – 99.98724751 | 360 to 310 |
| 99.985572 – 99.9740296 | 309 to 299 |
| 99.97589128 – 99.96258028 | 298 to 288 |
| 99.96146328 – 99.94424276 | 287 to 278 |
| 99.94098483 – 99.91929629 | 277 to 268 |
| 99.91836545 – 99.89081262 | 267 to 258 |
| 99.88643768 – 99.84845946 | 257 to 248 |
| 99.84510844 – 99.79959043 | 247 to 238 |
| 99.79679791 – 99.73294238 | 237 to 228 |
| 99.73005678 – 99.65475193 | 227 to 218 |
| 99.64888765 – 99.55273201 | 217 to 208 |
| 99.54919482 – 99.43609792 | 207 to 198 |
| 99.4200875 – 99.28958392 | 197 to 188 |
| 99.26473052 – 99.07781811 | 187 to 178 |
| 99.06329703 – 98.85683701 | 177 to 168 |
| 98.82509541 – 98.55710695 | 167 to 158 |
| 98.53104347 – 98.20040957 | 157 to 148 |
| 98.14939961 – 97.75686494 | 147 to 138 |
| 97.69477799 – 97.17648701 | 137 to 128 |
| 97.13841571 – 96.41990133 | 127 to 118 |
| 96.35511496 – 95.49744019 | 117 to 108 |
| 95.42678954 – 94.40128456 | 107 to 98 |
| 94.19473145 – 92.74709113 | 97 to 88 |
| 92.61891464 – 90.64227869 | 87 to 78 |
| 90.42902355 – 87.34180397 | 77 to 68 |
| 87.34180397 – 82.68016383 | 67 to 58 |
| 81.92571907 – 75.39020758 | 57 to 48 |
| 74.13450619 – 64.11300382 | 47 to 38 |
| 62.88839244 – 49.28762915 | 37 to 28 |
| 49.01228707 – 33.08815042 | 27 to 18 |
| 31.32570046 – 9.077538863 | 17 to 1 |
JEE Main January 2020 (Paper 1) Statistics
Below table represents the category and gender wise number of the candidates who participated in Paper 1:
| Category | Male | Female | Transgender | Total |
| General | 234049 | 102812 | 1 | 336862 |
| EWS | 57537 | 24586 | 0 | 82123 |
| SC | 56246 | 22602 | 0 | 78848 |
| ST | 22428 | 8913 | 0 | 31341 |
| OBC (NCL) | 234721 | 105113 | 2 | 339836 |
100 Percentilers of JEE Main January 2020 (Paper 1)
| S. No | Candidates Name | Application No. | State Code of Eligibility |
| 1 | Landa Jitendra | 200310065452 | Andhra Pradesh |
| 2 | Thadavarthi Vishnu Sri Sai Sankar | 200310404791 | Andhra Pradesh |
| 3 | Nishant Agarwal | 200310120506 | Delhi (NCT) |
| 4 | Nisarg Chadha | 200310012227 | Gujarat |
| 5 | Divyanshu Agarwal | 200310041891 | Haryana |
| 6 | Akhil Jain | 200310436560 | Rajasthan |
| 7 | Parth Dwivedi | 200310166791 | Rajasthan |
| 8 | Rongala Arun Siddardha | 200310594754 | Telangana |
| 9 | Chagari Koushal Kumar Reddy | 200310386279 | Telangana |
JEE Main Category-wise Cutoff (Trends of Past 3 Years)
The JEE Main cutoff scores of previous three years will help the candidates get an idea of JEE Main Cutoff 2020:
Previous Years’ JEE Main Cutoff
| Year | Common Rank List | OBC (NCL) | SC | ST | PWD | EWS (Gen) |
| 2019 | 89.7548849 | 74.3166557 | 54.0128155 | 44.3345172 | 0.1137173 | 78.2174869 |
| 2018 | 74 | 45 | 29 | 24 | -35 | NA |
| 2017 | 81 | 49 | 32 | 27 | 1 | NA |
JEE Main – Seat Matrix
After the declaration of JEE Main Result 2020 for April session, the best of total NTA scores of the candidates will be considered for admission. The seat intake capacity of premier engineering institutions has been provided in the table below.
JEE Main Seat Matrix 2020
| Institution | No. of Seats |
| IITs | 13,376 |
| NITs | 17,967 |
| IIITs | 4,023 |
| GFTIs | 4,683 |
JEE Advanced Eligibility Criteria
JEE Main result 2020 will show the qualifying status of candidates for JEE Advanced. Hence, knowing about the eligibility criteria of JEE Advanced will be helpful for the JEE Main aspirants.
JEE Main 2020 Performance – Candidates must have attained a place among top 250,000 (including all categories) in Paper 1 of JEE Main.
Category-wise distribution of top 250,000* candidates
| S.No | Category | No. of Top Candidates |
| 1 | Open | 96187 |
| 2 | Open-PwD | 5063 |
| 3 | Gen- EWS | 23750 |
| 4 | Gen- EWS (PwD) | 1250 |
| 5 | OBC-NCL | 64125 |
| 6 | OBC-NCL (PwD) | 3375 |
| 7 | SC | 35625 |
| 8 | SC- PwD | 1875 |
| 9 | ST | 17812 |
| 10 | ST- PwD | 938 |
- Age – Candidates born before October 1, 1995 (Five years relaxation to SC, ST and PwD candidates) will not be eligible for JEE Advanced 2020.
- Number of Attempts– A candidate should not have attempted JEE advanced more than once before attempting this exam this year.
- Qualification – A candidate should have appeared for the Class XII (or equivalent) examination for the first time in either 2019 or 2020 with Physics, Chemistry and Mathematics as compulsory subjects.
JEE Main Result – FAQs
Q. I had also attempted JEE Main January. Which JEE Main score will be considered?
A. The best of total NTA score from both of your attempts will be considered for further processing. If your January attempt’s score remains better than April session then it will be considered.
Q. Will NTA release the scores of January and April separately in JEE Main result 2020?
A. Yes, your final scorecard of JEE Main 2020 will show scores and ranks of both the sessions separately. The overall score as well as sectional scores of both the sessions will be displayed in JEE Main Scorecard 2020 along with your JEE Advanced qualifying status.
Q. Can I apply for revaluation of my JEE Main score?
A. No, the scorecard released by the authorities will be final. There shall be no provision for revaluation. Such a restriction on revaluation sometimes leaves aspirants puzzled and dissatisfied with their score.
Q. Will NTA send the JEE Main 2020 scorecard individually via post?
A. No, you will have to download your scorecard from the official website of JEE Main. Candidates are advised to take a printout of their JEE Main Scorecard 2020 until the admission process gets over.
Q. If my percentile remains same in both the sessions then how NTA will determine my JEE Main rank?
A. Refer the explanation on inter-se merit shown above in this article. It will help you understand the JEE Main tie-breaking process defined by NTA
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